Factorise: 12cdc2d2


Answer:

(1cd)(1+c+d)

Step by Step Explanation:
  1. We know that (a2b2)=(a+b)(ab)(i)(a+b)2=a2+2ab+b2(ii)
  2. We have: 12cdc2d2= 1(c2+d2+2cd)= 12(c+d)2[Using eq(ii)]= (1(c+d))(1+(c+d))[Using eq(i)]= (1cd)(1+c+d)
  3. Hence, 12cdc2d2= (1cd)(1+c+d).

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