A square of area 64 cm2 is inscribed into a semi-circle. What is the area of the semi-circle?
Answer:
40π cm2
- The following figure shows the square inscribed into a semi-circle,
Let's assume, a is the length of the side of the square.
Therefore, AB = BC = CD = DA = a,
The area of the square = a2 - According to the question, the area of the square is 64 cm2.
Therefore, a2 = 64 -----(1) - If we look at the figure carefully, we notice the OC is the radius of the semi-circle and 'O' is the center of the semi-circle.
Therefore, OA = OB =a 2 - In right angled triangle OBC,
OC2 = OB2 + BC2 [By the Pythagorean theorem.]
= (
)2 + a2a 2
=
+ a2a2 4
=5a2 4
=
[From equation (1)]5 × 64 4
=320 4
= 80 cm2 - Now, the area of the semi-circle =
π(OC)2 2
=π × 80 2
= 40π - Hence, the area of the semi-circle is 40π cm2.