Edugain Q&A

Please if you find the work out and solution. Thank you


A                            B                                             C                      D

I..............................I...............................................I.......................I

The distance from A to B is one-third of the distance form A to D

The distance from C to D is one-quanter of the distance from A to D.

The distance from B to C is 150 millimetres.

 

What is the distance from A to D? 

 

................. millimetres


A                                                            B                                                                                           C                                                                                   D

 

Length AB = 1/3 of AD

Length CD = 1/4 of AD

Length BC = 150 mm

 

So, Length AD = Length AB + Length BC + Length CD

AD = 1/3 AD + 150 mm + 1/4 AD

AD = 7/12 AD + 150 mm

( AD - 7/12 AD) = 150 mm

5/12 AD = 150 mm

AD = 360 mm

 

ANSWER = Distance from A to D is 360 millimeter

AB= 1/3AD

CD=1/4AD

BC=150mm

SOLUTION:

AB+BC+CD=AD

1/3AD+150+1/4AD=AD

7/12AD+150=AD

5/12AD = 150

AD=360


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